Inverse Laplace Transform of 1/(s − 3)
The inverse Laplace transform of 1/(s − 3) is e^(3t). See the partial fraction expansion and the transform pair used for each term, then edit F(s) to try your own.
L⁻¹{1/(s − 3)} = e^(3t). A pole in the right half plane means a growing exponential.
e.g. 2s+3
Expanded or factored, e.g. (s+1)(s^2+4)
The result
L⁻¹{1/(s − 3)} = e^(3t)
Partial fractions: 1/(s - 3)
- Invert 1/(s - 3) — L⁻¹{A/(s − a)^1} = A·t^0e^(at)/0!
A pole in the right half plane means a growing exponential.
More inverse transforms
Frequently asked questions
What is the inverse Laplace transform of 1/(s − 3)? ▾
It is f(t) = e^(3t). A pole in the right half plane means a growing exponential.
What are the partial fractions here? ▾
F(s) splits into 1/(s - 3), and each piece is inverted separately.
How can I check this answer? ▾
Transform e^(3t) forward again with the Laplace transform calculator — you should get back 1/(s − 3).
About this Calculator
The inverse Laplace transform of 1/(s − 3) is e^(3t). See the partial fraction expansion and the transform pair used for each term, then edit F(s) to try your own.