Laplace Transform of sin(2t)
The Laplace transform of sin(2t) is 2/(s^2 + 4). See the table rule behind it, then edit the function to transform anything else.
L{sin(2t)} = 2/(s^2 + 4). With a = 2 the transform is 2/(s² + 4).
Use t as the variable. Examples: t^3, e^(-2t), sin(3t), t*cos(2t), 4t^2+3. Write δ(t) as delta(t).
The result
L{sin(2t)} = 2/(s^2 + 4)
- L{sin(2t)} = 2/(s^2 + 4) Table rule: L{e^(at)sin(bt)} = b/((s − a)² + b²)
With a = 2 the transform is 2/(s² + 4).
More trigonometric transforms
Other transforms
Frequently asked questions
What is the Laplace transform of sin(2t)? ▾
L{sin(2t)} = 2/(s^2 + 4). With a = 2 the transform is 2/(s² + 4).
Which rule gives the transform of sin(2t)? ▾
L{e^(at)sin(bt)} = b/((s − a)² + b²) applied to sin(2t).
How do I get back from F(s) to f(t)? ▾
Use the inverse Laplace transform. Split F(s) into partial fractions and invert each piece with the same table read backwards — the inverse Laplace transform calculator does this step by step.
About this Calculator
The Laplace transform of sin(2t) is 2/(s^2 + 4). See the table rule behind it, then edit the function to transform anything else.