∫(x + y) ds along a line segment
∫C (x+y) ds along r(t) = (t, 2*t, 0) equals 3.35410197. A worked scalar field line integral with an editable calculator.
∫C (x+y) ds = 3.35410197. For a straight parametrisation the speed |r′(t)| is constant, so it factors out of the integral.
Example: x+y, x^2*y, sqrt(x^2+y^2). Use f = 1 to get arc length.
Curve C: r(t) = (x(t), y(t), z(t))
Leave z(t) as 0 for a plane curve
The setup
∫C (x+y) ds = 3.35410197
- Curve: r(t) = (t, 2*t, 0) for t from 0 to 1
- Arc length of the curve: 2.236068
- Type: scalar field line integral
For a straight parametrisation the speed |r′(t)| is constant, so it factors out of the integral.
More worked line integrals
Frequently asked questions
What is the value of this line integral? ▾
∫C (x+y) ds = 3.35410197. For a straight parametrisation the speed |r′(t)| is constant, so it factors out of the integral.
What curve is being integrated along? ▾
The curve is parametrised as r(t) = (t, 2*t, 0) for t from 0 to 1, and it has arc length 2.236068.
Does the direction of travel matter here? ▾
No. A scalar line integral is taken with respect to arc length, so travelling the curve backwards gives exactly the same value.
About this Calculator
∫C (x+y) ds along r(t) = (t, 2*t, 0) equals 3.35410197. A worked scalar field line integral with an editable calculator.