∫(x + y) ds along a line segment

∫C (x+y) ds along r(t) = (t, 2*t, 0) equals 3.35410197. A worked scalar field line integral with an editable calculator.

∫C (x+y) ds = 3.35410197. For a straight parametrisation the speed |r′(t)| is constant, so it factors out of the integral.

Example: x+y, x^2*y, sqrt(x^2+y^2). Use f = 1 to get arc length.

Curve C: r(t) = (x(t), y(t), z(t))

Leave z(t) as 0 for a plane curve

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Frequently asked questions

What is the value of this line integral?

∫C (x+y) ds = 3.35410197. For a straight parametrisation the speed |r′(t)| is constant, so it factors out of the integral.

What curve is being integrated along?

The curve is parametrised as r(t) = (t, 2*t, 0) for t from 0 to 1, and it has arc length 2.236068.

Does the direction of travel matter here?

No. A scalar line integral is taken with respect to arc length, so travelling the curve backwards gives exactly the same value.

About this Calculator

∫C (x+y) ds along r(t) = (t, 2*t, 0) equals 3.35410197. A worked scalar field line integral with an editable calculator.

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