Triple integral over the unit cube

∫₀¹∫₀¹∫₀¹ xyz dz dy dx = 1/8 ≈ 0.125. A worked triple integral in Cartesian coordinates, with an editable calculator preloaded with the limits.

∫₀¹∫₀¹∫₀¹ xyz dz dy dx = 1/8 ≈ 0.125. The limits are all constants, so the integral separates into three identical single integrals of ½ each.

dV = dz dy dx

In terms of x, y, z

Limits of integration

Inner limits may use the outer variables — e.g. 1-x, sqrt(1-x^2)

x fromtoconstants only
y fromtomay depend on x
z fromtomay depend on x, y
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Frequently asked questions

What is the value of ∫₀¹∫₀¹∫₀¹ xyz dz dy dx?

It evaluates to 1/8 ≈ 0.125. The limits are all constants, so the integral separates into three identical single integrals of ½ each.

Why Cartesian coordinates for this one?

The region is bounded by planes and graphs, so rectangular limits describe it directly with no change of variables needed.

Do I need to include the Jacobian myself?

There is no Jacobian in Cartesian coordinates — dV is simply dz dy dx.

About this Calculator

∫₀¹∫₀¹∫₀¹ xyz dz dy dx = 1/8 ≈ 0.125. A worked triple integral in Cartesian coordinates, with an editable calculator preloaded with the limits.

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